1x=(1^2)-(2^1)-(3^3)

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Solution for 1x=(1^2)-(2^1)-(3^3) equation: 



1x=(1^2)-(2^1)-(3^3)

We move all terms to the left:

1x-((1^2)-(2^1)-(3^3))=0

We add all the numbers together, and all the variables

x+28=0

We move all terms containing x to the left, all other terms to the right

x=-28

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